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Subject: Re: is a point 'inside' a bezier?



Who needs a factorial when you're dealing with 0, 1, and 2? They're all
their own factorials.

Anyhow that equation looks pretty complicated for a simple implicit
quadratic, especially since the result came out so simple. Can you
elaborate on what you're doing?

Thanks!
Dan


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Re: is a point 'inside' a bezier?

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